Images of Phi Part II

A Ulam spiral testing each number for if(Math.round((n * Math.PI)/1.618)%9==0)

Same idea, swapping out mod 9 with mod 5:

Calculation per dot: (Math.round(Math.sqrt(Math.pow(n,2))*1.618/2)%5==0)

Calculation per dot: (Math.round(Math.sqrt(n*1.618)/2)%5==0)

Calculation per dot: (Math.round(Math.sqrt(n*1.618))%5==0)

Calculation per dot: (Math.round(Math.sqrt(n*2))%5==0)

Here are the selected primes up to 13693 from the previous image.