`if(Math.round(Math.sqrt(Math.pow(`

. I'm not sure what the significance is of multiplying PI with the Golden Mean. But it sure looks cool.*n*,2))*(1.6180339887*3.14159265)/2)%5==0){//paint a dot}

A little more number crunching: `if(Math.round(Math.sqrt(Math.pow(pInt, (Math.sqrt(2)+1) ))*(1.6180339887*3.14159265)/2)%2==0){//paint weird pattern}`

Tighten up the resolution and you approach a nice pattern for a wool rug.

Note that the picture gets clearer the farther from center you go. It seems there is simply more mathematical "space" for the pattern to be expressed.

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